WebFeb 22, 2024 · Data Structures & Algorithms in Python; Explore More Self-Paced Courses; Programming Languages. C++ Programming - Beginner to Advanced; Java Programming - Beginner to Advanced; C Programming - Beginner to Advanced; Web Development. Full Stack Development with React & Node JS(Live) Java Backend Development(Live) … WebMar 3, 2012 · As for your first question: "if item is in my_list:" is perfectly fine and should work if item equals one of the elements inside my_list.The item must exactly match an item in the list. For instance, "abc" and "ABC" do not match. Floating point values in particular may suffer from inaccuracy. For instance, 1 - 1/3 != 2/3. As for your second question: …
python find index of element that is not code example
WebMar 23, 2012 · I guess the most effective way to find duplicates in a list is: from collections import Counter def duplicates (values): dups = Counter (values) - Counter (set (values)) return list (dups.keys ()) print (duplicates ( [1,2,3,6,5,2])) It uses Counter once on all the elements, and then on all unique elements. WebBut using any() is definitely more typical Python style than a for loop as in e.g. RichieHindle's answer, Of course there is a hidden loop in the ... is in the list made up of elements with the index you're interested in. Share. Improve this answer. Follow answered Jul 20, 2009 at 23:48. Markus Markus. 3,397 3 3 gold badges 23 23 silver ... breach medical meaning
Python: Find in list - Stack Overflow
WebEXPLANATIONS: (1) You can use NumPy's setdiff1d (array1,array2,assume_unique=False). assume_unique asks the user IF the arrays ARE ALREADY UNIQUE. If False, then the unique elements are determined first. If True, the function will assume that the elements are already unique AND function will skip … WebJan 16, 2024 · It is because when you executed aList = [i for i in aList if i not in bList ], you replaced the content of your aList from [1,2] to [1].. And hence, bList ended up holding both [2,3] because your aList is just [1] while executing bList = [i for i in bList if i not in aList ]. In order to make your logic work, you may store the aList and bList in different variable. WebApr 10, 2024 · Basically, the final "k" loop (k = 39), will be the one repeated over all sublists. Making it more simple: IF I do this: list [0] [3] = 5. the fourth element of ALL sublists will be 5, not only the fourth element of the FIRST sublist. I don't want list [5] [3] to be 5 as well. Because the result will be that the final loop will be the one ... breach meaning law