WebApr 18, 2024 · Given: l, m, n are the direction cosines of the line x - 1 = 2 (y + 3) = 1 - z. The given equation of lines can be re-written as x − 1 1 = y + 3 1 2 = z − 1 − 1. So, by comparing the equation x − 1 1 = y + 3 1 2 = z − 1 − 1 with x − x 1 a = y − y 1 b = z − z 1 c we get. ⇒ a = 1, b = 1/2 and c = - 1. As we know, if a, b, c ... WebApr 10, 2024 · Given: Equation of line is 2x = 3y = 5 - 4z. We will first be converting the above expression in standard form for comparison, i.e. we need to get rid of coefficients of x, y, and z, i.e. 2, 3, and 4 respectively. LCM of 2, 3, and 4 is 12. ∴ Dividing the above equation by 12, we get: ⇒ 2 x 12 = 3 y 12 = 5 − 4 z 12. ⇒ x 6 = y 4 = z − 5 ...
Direction Ratios of a Line and Direction Cosines with Examples
Web5. If cos α,cos β, cos γ are the direction cosines of a vector a, then cos 2α,cos 2β, cos 2γ is equal to. 6. The angle between the lines whose direction cosines satisfy the equations l +m + n = 0 and l2 = m2 + n2 is. 7. The line 2x−1 = 3y−2 = 4z−3 meets the plane 2x +3y − z = −4 in the point. WebFind the direction cosines of the line ` ( x + 2 ) /(2) = ( 2 y - 5) /( 3 ) , z = - 1 ` blazor app change favicon
Find the direction cosine of the following lines: 3-x/-1 = 2y-1/2 …
WebFind the direction cosines of the line 2x+2 = 62y−7 = 65−z. then the vector equation of the line through the point A (1, 2, 3) and parallel to the given line can be expressed as … WebMar 30, 2024 · Question 4 (OR 2nd question) Find the direction cosines of the line: (𝑥 − 1)/2 = –y = (𝑧 + 1)/2 Given line (𝑥 − 1)/2 = –y = (𝑧 + 1)/2 (𝑥 − 1)/2 = (−𝑦)/1 = (𝑧 + 1)/2 (𝑥 − 1)/2 = 𝑦/(−1) = (𝑧 + 1)/2 So, direction ratios are 2, –1, 2 … WebMay 26, 2024 · A line is perpendicular to two lines having direction ratios 1, -2, -2 and 0, 2, 1. The direction cosines of the line are A. -2/3, 1/3, 2/3 asked Aug 12, 2024 in Straight Lines by Nikunj ( 39.7k points) blazor app changing reconnect timeout